5a(3-a)+6a^2-13a=2a+1a^2

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Solution for 5a(3-a)+6a^2-13a=2a+1a^2 equation:


Simplifying
5a(3 + -1a) + 6a2 + -13a = 2a + 1a2
(3 * 5a + -1a * 5a) + 6a2 + -13a = 2a + 1a2
(15a + -5a2) + 6a2 + -13a = 2a + 1a2

Reorder the terms:
15a + -13a + -5a2 + 6a2 = 2a + 1a2

Combine like terms: 15a + -13a = 2a
2a + -5a2 + 6a2 = 2a + 1a2

Combine like terms: -5a2 + 6a2 = 1a2
2a + 1a2 = 2a + 1a2

Add '-2a' to each side of the equation.
2a + -2a + 1a2 = 2a + -2a + 1a2

Combine like terms: 2a + -2a = 0
0 + 1a2 = 2a + -2a + 1a2
1a2 = 2a + -2a + 1a2

Combine like terms: 2a + -2a = 0
1a2 = 0 + 1a2
1a2 = 1a2

Add '-1a2' to each side of the equation.
1a2 + -1a2 = 1a2 + -1a2

Combine like terms: 1a2 + -1a2 = 0
0 = 1a2 + -1a2

Combine like terms: 1a2 + -1a2 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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